3(2x+4)-5(x-7)+8=2(x-6)+18

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Solution for 3(2x+4)-5(x-7)+8=2(x-6)+18 equation: 



3(2x+4)-5(x-7)+8=2(x-6)+18

We move all terms to the left:

3(2x+4)-5(x-7)+8-(2(x-6)+18)=0

We multiply parentheses

6x-5x-(2(x-6)+18)+12+35+8=0



We calculate terms in parentheses: -(2(x-6)+18), so:

2(x-6)+18

We multiply parentheses

2x-12+18

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

x-(2x+6)+55=0

We get rid of parentheses

x-2x-6+55=0

We add all the numbers together, and all the variables

-1x+49=0

We move all terms containing x to the left, all other terms to the right

-x=-49

x=-49/-1

x=+49

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