3(2x+4)-7(8-3x)=12(2x+3)

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Solution for 3(2x+4)-7(8-3x)=12(2x+3) equation: 



3(2x+4)-7(8-3x)=12(2x+3)

We move all terms to the left:

3(2x+4)-7(8-3x)-(12(2x+3))=0

We add all the numbers together, and all the variables

3(2x+4)-7(-3x+8)-(12(2x+3))=0

We multiply parentheses

6x+21x-(12(2x+3))+12-56=0



We calculate terms in parentheses: -(12(2x+3)), so:

12(2x+3)

We multiply parentheses

24x+36

Back to the equation:

-(24x+36)



We add all the numbers together, and all the variables

27x-(24x+36)-44=0

We get rid of parentheses

27x-24x-36-44=0

We add all the numbers together, and all the variables

3x-80=0

We move all terms containing x to the left, all other terms to the right

3x=80

x=80/3

x=26+2/3

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