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3(2x+4)=2(x+2)+2(3x+2)
We move all terms to the left:
3(2x+4)-(2(x+2)+2(3x+2))=0
We multiply parentheses
6x-(2(x+2)+2(3x+2))+12=0
We calculate terms in parentheses: -(2(x+2)+2(3x+2)), so:We get rid of parentheses
2(x+2)+2(3x+2)
We multiply parentheses
2x+6x+4+4
We add all the numbers together, and all the variables
8x+8
Back to the equation:
-(8x+8)
6x-8x-8+12=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2
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