3(2x+4)=3(x-5)+10

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Solution for 3(2x+4)=3(x-5)+10 equation: 



3(2x+4)=3(x-5)+10

We move all terms to the left:

3(2x+4)-(3(x-5)+10)=0

We multiply parentheses

6x-(3(x-5)+10)+12=0



We calculate terms in parentheses: -(3(x-5)+10), so:

3(x-5)+10

We multiply parentheses

3x-15+10

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We get rid of parentheses

6x-3x+5+12=0

We add all the numbers together, and all the variables

3x+17=0

We move all terms containing x to the left, all other terms to the right

3x=-17

x=-17/3

x=-5+2/3

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