3(2x+4)=3x+48

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Solution for 3(2x+4)=3x+48 equation: 



3(2x+4)=3x+48

We move all terms to the left:

3(2x+4)-(3x+48)=0

We multiply parentheses

6x-(3x+48)+12=0

We get rid of parentheses

6x-3x-48+12=0

We add all the numbers together, and all the variables

3x-36=0

We move all terms containing x to the left, all other terms to the right

3x=36

x=36/3

x=12

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