3(2x+4)=4(3x+-1)

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Solution for 3(2x+4)=4(3x+-1) equation: 



3(2x+4)=4(3x+-1)

We move all terms to the left:

3(2x+4)-(4(3x+-1))=0

We add all the numbers together, and all the variables

3(2x+4)-(4(3x-1))=0

We multiply parentheses

6x-(4(3x-1))+12=0



We calculate terms in parentheses: -(4(3x-1)), so:

4(3x-1)

We multiply parentheses

12x-4

Back to the equation:

-(12x-4)



We get rid of parentheses

6x-12x+4+12=0

We add all the numbers together, and all the variables

-6x+16=0

We move all terms containing x to the left, all other terms to the right

-6x=-16

x=-16/-6

x=2+2/3

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