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3(2x+4)=4(5x+3)
We move all terms to the left:
3(2x+4)-(4(5x+3))=0
We multiply parentheses
6x-(4(5x+3))+12=0
We calculate terms in parentheses: -(4(5x+3)), so:We get rid of parentheses
4(5x+3)
We multiply parentheses
20x+12
Back to the equation:
-(20x+12)
6x-20x-12+12=0
We add all the numbers together, and all the variables
-14x=0
x=0/-14
x=0
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