3(2x+4)=4x+63(2x+4)=4x+6

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Solution for 3(2x+4)=4x+63(2x+4)=4x+6 equation: 



3(2x+4)=4x+63(2x+4)=4x+6

We move all terms to the left:

3(2x+4)-(4x+63(2x+4))=0

We multiply parentheses

6x-(4x+63(2x+4))+12=0



We calculate terms in parentheses: -(4x+63(2x+4)), so:

4x+63(2x+4)

We multiply parentheses

4x+126x+252

We add all the numbers together, and all the variables

130x+252

Back to the equation:

-(130x+252)



We get rid of parentheses

6x-130x-252+12=0

We add all the numbers together, and all the variables

-124x-240=0

We move all terms containing x to the left, all other terms to the right

-124x=240

x=240/-124

x=-1+29/31

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