3(2x+4)=7(x+1)

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Solution for 3(2x+4)=7(x+1) equation: 



3(2x+4)=7(x+1)

We move all terms to the left:

3(2x+4)-(7(x+1))=0

We multiply parentheses

6x-(7(x+1))+12=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We get rid of parentheses

6x-7x-7+12=0

We add all the numbers together, and all the variables

-1x+5=0

We move all terms containing x to the left, all other terms to the right

-x=-5

x=-5/-1

x=+5

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