3(2x+4)=7-(x+5)

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Solution for 3(2x+4)=7-(x+5) equation: 



3(2x+4)=7-(x+5)

We move all terms to the left:

3(2x+4)-(7-(x+5))=0

We multiply parentheses

6x-(7-(x+5))+12=0



We calculate terms in parentheses: -(7-(x+5)), so:

7-(x+5)

determiningTheFunctionDomain
-(x+5)+7

We get rid of parentheses

-x-5+7

We add all the numbers together, and all the variables

-1x+2

Back to the equation:

-(-1x+2)



We get rid of parentheses

6x+1x-2+12=0

We add all the numbers together, and all the variables

7x+10=0

We move all terms containing x to the left, all other terms to the right

7x=-10

x=-10/7

x=-1+3/7

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