3(2x+5)+2(x-4)=63

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Solution for 3(2x+5)+2(x-4)=63 equation: 



3(2x+5)+2(x-4)=63

We move all terms to the left:

3(2x+5)+2(x-4)-(63)=0

We multiply parentheses

6x+2x+15-8-63=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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