3(2x+5)+4(3x+1)=109

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Solution for 3(2x+5)+4(3x+1)=109 equation:


Simplifying
3(2x + 5) + 4(3x + 1) = 109

Reorder the terms:
3(5 + 2x) + 4(3x + 1) = 109
(5 * 3 + 2x * 3) + 4(3x + 1) = 109
(15 + 6x) + 4(3x + 1) = 109

Reorder the terms:
15 + 6x + 4(1 + 3x) = 109
15 + 6x + (1 * 4 + 3x * 4) = 109
15 + 6x + (4 + 12x) = 109

Reorder the terms:
15 + 4 + 6x + 12x = 109

Combine like terms: 15 + 4 = 19
19 + 6x + 12x = 109

Combine like terms: 6x + 12x = 18x
19 + 18x = 109

Solving
19 + 18x = 109

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + 18x = 109 + -19

Combine like terms: 19 + -19 = 0
0 + 18x = 109 + -19
18x = 109 + -19

Combine like terms: 109 + -19 = 90
18x = 90

Divide each side by '18'.
x = 5

Simplifying
x = 5

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