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3(2x+5)+x=3-4(x+2)
We move all terms to the left:
3(2x+5)+x-(3-4(x+2))=0
We add all the numbers together, and all the variables
x+3(2x+5)-(3-4(x+2))=0
We multiply parentheses
x+6x-(3-4(x+2))+15=0
We calculate terms in parentheses: -(3-4(x+2)), so:We add all the numbers together, and all the variables
3-4(x+2)
determiningTheFunctionDomain -4(x+2)+3
We multiply parentheses
-4x-8+3
We add all the numbers together, and all the variables
-4x-5
Back to the equation:
-(-4x-5)
7x-(-4x-5)+15=0
We get rid of parentheses
7x+4x+5+15=0
We add all the numbers together, and all the variables
11x+20=0
We move all terms containing x to the left, all other terms to the right
11x=-20
x=-20/11
x=-1+9/11
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