3(2x+5)-(4-3x)=1-8(3-x)

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Solution for 3(2x+5)-(4-3x)=1-8(3-x) equation: 



3(2x+5)-(4-3x)=1-8(3-x)

We move all terms to the left:

3(2x+5)-(4-3x)-(1-8(3-x))=0

We add all the numbers together, and all the variables

3(2x+5)-(-3x+4)-(1-8(-1x+3))=0

We multiply parentheses

6x-(-3x+4)-(1-8(-1x+3))+15=0

We get rid of parentheses

6x+3x-(1-8(-1x+3))-4+15=0



We calculate terms in parentheses: -(1-8(-1x+3)), so:

1-8(-1x+3)

determiningTheFunctionDomain
-8(-1x+3)+1

We multiply parentheses

8x-24+1

We add all the numbers together, and all the variables

8x-23

Back to the equation:

-(8x-23)



We add all the numbers together, and all the variables

9x-(8x-23)+11=0

We get rid of parentheses

9x-8x+23+11=0

We add all the numbers together, and all the variables

x+34=0

We move all terms containing x to the left, all other terms to the right

x=-34

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