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3(2x+5)-22=3/x
We move all terms to the left:
3(2x+5)-22-(3/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3(2x+5)-(+3/x)-22=0
We multiply parentheses
6x-(+3/x)+15-22=0
We get rid of parentheses
6x-3/x+15-22=0
We multiply all the terms by the denominator
6x*x+15*x-22*x-3=0
We add all the numbers together, and all the variables
-7x+6x*x-3=0
Wy multiply elements
6x^2-7x-3=0
a = 6; b = -7; c = -3;
Δ = b2-4ac
Δ = -72-4·6·(-3)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-11}{2*6}=\frac{-4}{12} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+11}{2*6}=\frac{18}{12} =1+1/2 $
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