3(2x+5)-3(3x-4)/2=9(2x-7)/2

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Solution for 3(2x+5)-3(3x-4)/2=9(2x-7)/2 equation: 



3(2x+5)-3(3x-4)/2=9(2x-7)/2

We move all terms to the left:

3(2x+5)-3(3x-4)/2-(9(2x-7)/2)=0

We multiply parentheses

6x-3(3x-4)/2-(9(2x-7)/2)+15=0

We calculate fractions


6x+15=0

We move all terms containing x to the left, all other terms to the right

6x=-15

x=-15/6

x=-2+1/2

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