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3(2x+5)-3x+7=12x-3(2+x)
We move all terms to the left:
3(2x+5)-3x+7-(12x-3(2+x))=0
We add all the numbers together, and all the variables
3(2x+5)-3x-(12x-3(x+2))+7=0
We add all the numbers together, and all the variables
-3x+3(2x+5)-(12x-3(x+2))+7=0
We multiply parentheses
-3x+6x-(12x-3(x+2))+15+7=0
We calculate terms in parentheses: -(12x-3(x+2)), so:We add all the numbers together, and all the variables
12x-3(x+2)
We multiply parentheses
12x-3x-6
We add all the numbers together, and all the variables
9x-6
Back to the equation:
-(9x-6)
3x-(9x-6)+22=0
We get rid of parentheses
3x-9x+6+22=0
We add all the numbers together, and all the variables
-6x+28=0
We move all terms containing x to the left, all other terms to the right
-6x=-28
x=-28/-6
x=4+2/3
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