3(2x+5)-8(x-1)=6(2x+3)

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Solution for 3(2x+5)-8(x-1)=6(2x+3) equation: 



3(2x+5)-8(x-1)=6(2x+3)

We move all terms to the left:

3(2x+5)-8(x-1)-(6(2x+3))=0

We multiply parentheses

6x-8x-(6(2x+3))+15+8=0



We calculate terms in parentheses: -(6(2x+3)), so:

6(2x+3)

We multiply parentheses

12x+18

Back to the equation:

-(12x+18)



We add all the numbers together, and all the variables

-2x-(12x+18)+23=0

We get rid of parentheses

-2x-12x-18+23=0

We add all the numbers together, and all the variables

-14x+5=0

We move all terms containing x to the left, all other terms to the right

-14x=-5

x=-5/-14

x=5/14

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