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3(2x+5)=2(5x-4)
We move all terms to the left:
3(2x+5)-(2(5x-4))=0
We multiply parentheses
6x-(2(5x-4))+15=0
We calculate terms in parentheses: -(2(5x-4)), so:We get rid of parentheses
2(5x-4)
We multiply parentheses
10x-8
Back to the equation:
-(10x-8)
6x-10x+8+15=0
We add all the numbers together, and all the variables
-4x+23=0
We move all terms containing x to the left, all other terms to the right
-4x=-23
x=-23/-4
x=5+3/4
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