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3(2x+5)=3(3x+2)
We move all terms to the left:
3(2x+5)-(3(3x+2))=0
We multiply parentheses
6x-(3(3x+2))+15=0
We calculate terms in parentheses: -(3(3x+2)), so:We get rid of parentheses
3(3x+2)
We multiply parentheses
9x+6
Back to the equation:
-(9x+6)
6x-9x-6+15=0
We add all the numbers together, and all the variables
-3x+9=0
We move all terms containing x to the left, all other terms to the right
-3x=-9
x=-9/-3
x=+3
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