3(2x+5)=4+2(2x+1)

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Solution for 3(2x+5)=4+2(2x+1) equation: 



3(2x+5)=4+2(2x+1)

We move all terms to the left:

3(2x+5)-(4+2(2x+1))=0

We multiply parentheses

6x-(4+2(2x+1))+15=0



We calculate terms in parentheses: -(4+2(2x+1)), so:

4+2(2x+1)

determiningTheFunctionDomain
2(2x+1)+4

We multiply parentheses

4x+2+4

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We get rid of parentheses

6x-4x-6+15=0

We add all the numbers together, and all the variables

2x+9=0

We move all terms containing x to the left, all other terms to the right

2x=-9

x=-9/2

x=-4+1/2

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