3(2x+5)=4x+35

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Solution for 3(2x+5)=4x+35 equation: 



3(2x+5)=4x+35

We move all terms to the left:

3(2x+5)-(4x+35)=0

We multiply parentheses

6x-(4x+35)+15=0

We get rid of parentheses

6x-4x-35+15=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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