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3(2x+5)=5(4+x)
We move all terms to the left:
3(2x+5)-(5(4+x))=0
We add all the numbers together, and all the variables
3(2x+5)-(5(x+4))=0
We multiply parentheses
6x-(5(x+4))+15=0
We calculate terms in parentheses: -(5(x+4)), so:We get rid of parentheses
5(x+4)
We multiply parentheses
5x+20
Back to the equation:
-(5x+20)
6x-5x-20+15=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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