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3(2x+5)=5+(5x-9)
We move all terms to the left:
3(2x+5)-(5+(5x-9))=0
We multiply parentheses
6x-(5+(5x-9))+15=0
We calculate terms in parentheses: -(5+(5x-9)), so:We get rid of parentheses
5+(5x-9)
determiningTheFunctionDomain (5x-9)+5
We get rid of parentheses
5x-9+5
We add all the numbers together, and all the variables
5x-4
Back to the equation:
-(5x-4)
6x-5x+4+15=0
We add all the numbers together, and all the variables
x+19=0
We move all terms containing x to the left, all other terms to the right
x=-19
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