3(2x+5)=8-2(2-3x)+11

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Solution for 3(2x+5)=8-2(2-3x)+11 equation: 



3(2x+5)=8-2(2-3x)+11

We move all terms to the left:

3(2x+5)-(8-2(2-3x)+11)=0

We add all the numbers together, and all the variables

3(2x+5)-(8-2(-3x+2)+11)=0

We multiply parentheses

6x-(8-2(-3x+2)+11)+15=0



We calculate terms in parentheses: -(8-2(-3x+2)+11), so:

8-2(-3x+2)+11

determiningTheFunctionDomain
-2(-3x+2)+8+11

We add all the numbers together, and all the variables

-2(-3x+2)+19

We multiply parentheses

6x-4+19

We add all the numbers together, and all the variables

6x+15

Back to the equation:

-(6x+15)



We get rid of parentheses

6x-6x-15+15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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