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3(2x+5)=8-2(2-3x)+11
We move all terms to the left:
3(2x+5)-(8-2(2-3x)+11)=0
We add all the numbers together, and all the variables
3(2x+5)-(8-2(-3x+2)+11)=0
We multiply parentheses
6x-(8-2(-3x+2)+11)+15=0
We calculate terms in parentheses: -(8-2(-3x+2)+11), so:We get rid of parentheses
8-2(-3x+2)+11
determiningTheFunctionDomain -2(-3x+2)+8+11
We add all the numbers together, and all the variables
-2(-3x+2)+19
We multiply parentheses
6x-4+19
We add all the numbers together, and all the variables
6x+15
Back to the equation:
-(6x+15)
6x-6x-15+15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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