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3(2x+5)=9(10-x)
We move all terms to the left:
3(2x+5)-(9(10-x))=0
We add all the numbers together, and all the variables
3(2x+5)-(9(-1x+10))=0
We multiply parentheses
6x-(9(-1x+10))+15=0
We calculate terms in parentheses: -(9(-1x+10)), so:We get rid of parentheses
9(-1x+10)
We multiply parentheses
-9x+90
Back to the equation:
-(-9x+90)
6x+9x-90+15=0
We add all the numbers together, and all the variables
15x-75=0
We move all terms containing x to the left, all other terms to the right
15x=75
x=75/15
x=5
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