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3(2x+5)=9(4-3x)
We move all terms to the left:
3(2x+5)-(9(4-3x))=0
We add all the numbers together, and all the variables
3(2x+5)-(9(-3x+4))=0
We multiply parentheses
6x-(9(-3x+4))+15=0
We calculate terms in parentheses: -(9(-3x+4)), so:We get rid of parentheses
9(-3x+4)
We multiply parentheses
-27x+36
Back to the equation:
-(-27x+36)
6x+27x-36+15=0
We add all the numbers together, and all the variables
33x-21=0
We move all terms containing x to the left, all other terms to the right
33x=21
x=21/33
x=7/11
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