3(2x+5)=x+4-3(x-2)

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Solution for 3(2x+5)=x+4-3(x-2) equation:



3(2x+5)=x+4-3(x-2)
We move all terms to the left:
3(2x+5)-(x+4-3(x-2))=0
We multiply parentheses
6x-(x+4-3(x-2))+15=0
We calculate terms in parentheses: -(x+4-3(x-2)), so:
x+4-3(x-2)
determiningTheFunctionDomain x-3(x-2)+4
We multiply parentheses
x-3x+6+4
We add all the numbers together, and all the variables
-2x+10
Back to the equation:
-(-2x+10)
We get rid of parentheses
6x+2x-10+15=0
We add all the numbers together, and all the variables
8x+5=0
We move all terms containing x to the left, all other terms to the right
8x=-5
x=-5/8
x=-5/8

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