3(2x+5)=x+4-3(x-2)

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Solution for 3(2x+5)=x+4-3(x-2) equation: 



3(2x+5)=x+4-3(x-2)

We move all terms to the left:

3(2x+5)-(x+4-3(x-2))=0

We multiply parentheses

6x-(x+4-3(x-2))+15=0



We calculate terms in parentheses: -(x+4-3(x-2)), so:

x+4-3(x-2)

determiningTheFunctionDomain
x-3(x-2)+4

We multiply parentheses

x-3x+6+4

We add all the numbers together, and all the variables

-2x+10

Back to the equation:

-(-2x+10)



We get rid of parentheses

6x+2x-10+15=0

We add all the numbers together, and all the variables

8x+5=0

We move all terms containing x to the left, all other terms to the right

8x=-5

x=-5/8

x=-5/8

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