3(2x+6)+7x=8+8(4x+6)

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Solution for 3(2x+6)+7x=8+8(4x+6) equation: 



3(2x+6)+7x=8+8(4x+6)

We move all terms to the left:

3(2x+6)+7x-(8+8(4x+6))=0

We add all the numbers together, and all the variables

7x+3(2x+6)-(8+8(4x+6))=0

We multiply parentheses

7x+6x-(8+8(4x+6))+18=0



We calculate terms in parentheses: -(8+8(4x+6)), so:

8+8(4x+6)

determiningTheFunctionDomain
8(4x+6)+8

We multiply parentheses

32x+48+8

We add all the numbers together, and all the variables

32x+56

Back to the equation:

-(32x+56)



We add all the numbers together, and all the variables

13x-(32x+56)+18=0

We get rid of parentheses

13x-32x-56+18=0

We add all the numbers together, and all the variables

-19x-38=0

We move all terms containing x to the left, all other terms to the right

-19x=38

x=38/-19

x=-2

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