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3(2x+6)8x=46
We move all terms to the left:
3(2x+6)8x-(46)=0
We multiply parentheses
48x^2+144x-46=0
a = 48; b = 144; c = -46;
Δ = b2-4ac
Δ = 1442-4·48·(-46)
Δ = 29568
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{29568}=\sqrt{64*462}=\sqrt{64}*\sqrt{462}=8\sqrt{462}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(144)-8\sqrt{462}}{2*48}=\frac{-144-8\sqrt{462}}{96} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(144)+8\sqrt{462}}{2*48}=\frac{-144+8\sqrt{462}}{96} $
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