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3(2x+7)=2(3x-5)+31
We move all terms to the left:
3(2x+7)-(2(3x-5)+31)=0
We multiply parentheses
6x-(2(3x-5)+31)+21=0
We calculate terms in parentheses: -(2(3x-5)+31), so:We get rid of parentheses
2(3x-5)+31
We multiply parentheses
6x-10+31
We add all the numbers together, and all the variables
6x+21
Back to the equation:
-(6x+21)
6x-6x-21+21=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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