3(2x-1)+(x-7)=3(x+1)-(-3x-1)+3x+2

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Solution for 3(2x-1)+(x-7)=3(x+1)-(-3x-1)+3x+2 equation: 



3(2x-1)+(x-7)=3(x+1)-(-3x-1)+3x+2

We move all terms to the left:

3(2x-1)+(x-7)-(3(x+1)-(-3x-1)+3x+2)=0

We multiply parentheses

6x+(x-7)-(3(x+1)-(-3x-1)+3x+2)-3=0

We get rid of parentheses

6x+x-(3(x+1)-(-3x-1)+3x+2)-7-3=0



We calculate terms in parentheses: -(3(x+1)-(-3x-1)+3x+2), so:

3(x+1)-(-3x-1)+3x+2

We add all the numbers together, and all the variables

3x+3(x+1)-(-3x-1)+2

We multiply parentheses

3x+3x-(-3x-1)+3+2

We get rid of parentheses

3x+3x+3x+1+3+2

We add all the numbers together, and all the variables

9x+6

Back to the equation:

-(9x+6)



We add all the numbers together, and all the variables

7x-(9x+6)-10=0

We get rid of parentheses

7x-9x-6-10=0

We add all the numbers together, and all the variables

-2x-16=0

We move all terms containing x to the left, all other terms to the right

-2x=16

x=16/-2

x=-8

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