3(2x-1)+2(3-x)=4(2x+5)+7x-5

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Solution for 3(2x-1)+2(3-x)=4(2x+5)+7x-5 equation: 



3(2x-1)+2(3-x)=4(2x+5)+7x-5

We move all terms to the left:

3(2x-1)+2(3-x)-(4(2x+5)+7x-5)=0

We add all the numbers together, and all the variables

3(2x-1)+2(-1x+3)-(4(2x+5)+7x-5)=0

We multiply parentheses

6x-2x-(4(2x+5)+7x-5)-3+6=0



We calculate terms in parentheses: -(4(2x+5)+7x-5), so:

4(2x+5)+7x-5

We add all the numbers together, and all the variables

7x+4(2x+5)-5

We multiply parentheses

7x+8x+20-5

We add all the numbers together, and all the variables

15x+15

Back to the equation:

-(15x+15)



We add all the numbers together, and all the variables

4x-(15x+15)+3=0

We get rid of parentheses

4x-15x-15+3=0

We add all the numbers together, and all the variables

-11x-12=0

We move all terms containing x to the left, all other terms to the right

-11x=12

x=12/-11

x=-1+1/11

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