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3(2x-1)+2(3x-2)=29
We move all terms to the left:
3(2x-1)+2(3x-2)-(29)=0
We multiply parentheses
6x+6x-3-4-29=0
We add all the numbers together, and all the variables
12x-36=0
We move all terms containing x to the left, all other terms to the right
12x=36
x=36/12
x=3
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