3(2x-1)+2(3x-2)=29

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Solution for 3(2x-1)+2(3x-2)=29 equation: 



3(2x-1)+2(3x-2)=29

We move all terms to the left:

3(2x-1)+2(3x-2)-(29)=0

We multiply parentheses

6x+6x-3-4-29=0

We add all the numbers together, and all the variables

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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