3(2x-1)+2x-7=3(x+1)-(-3x-1)+3x+2

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Solution for 3(2x-1)+2x-7=3(x+1)-(-3x-1)+3x+2 equation: 



3(2x-1)+2x-7=3(x+1)-(-3x-1)+3x+2

We move all terms to the left:

3(2x-1)+2x-7-(3(x+1)-(-3x-1)+3x+2)=0

We add all the numbers together, and all the variables

2x+3(2x-1)-(3(x+1)-(-3x-1)+3x+2)-7=0

We multiply parentheses

2x+6x-(3(x+1)-(-3x-1)+3x+2)-3-7=0



We calculate terms in parentheses: -(3(x+1)-(-3x-1)+3x+2), so:

3(x+1)-(-3x-1)+3x+2

We add all the numbers together, and all the variables

3x+3(x+1)-(-3x-1)+2

We multiply parentheses

3x+3x-(-3x-1)+3+2

We get rid of parentheses

3x+3x+3x+1+3+2

We add all the numbers together, and all the variables

9x+6

Back to the equation:

-(9x+6)



We add all the numbers together, and all the variables

8x-(9x+6)-10=0

We get rid of parentheses

8x-9x-6-10=0

We add all the numbers together, and all the variables

-1x-16=0

We move all terms containing x to the left, all other terms to the right

-x=16

x=16/-1

x=-16

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