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3(2x-1)+4=3-5(1-x)
We move all terms to the left:
3(2x-1)+4-(3-5(1-x))=0
We add all the numbers together, and all the variables
3(2x-1)-(3-5(-1x+1))+4=0
We multiply parentheses
6x-(3-5(-1x+1))-3+4=0
We calculate terms in parentheses: -(3-5(-1x+1)), so:We add all the numbers together, and all the variables
3-5(-1x+1)
determiningTheFunctionDomain -5(-1x+1)+3
We multiply parentheses
5x-5+3
We add all the numbers together, and all the variables
5x-2
Back to the equation:
-(5x-2)
6x-(5x-2)+1=0
We get rid of parentheses
6x-5x+2+1=0
We add all the numbers together, and all the variables
x+3=0
We move all terms containing x to the left, all other terms to the right
x=-3
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