3(2x-1)+5(x+2)=40

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Solution for 3(2x-1)+5(x+2)=40 equation:


Simplifying
3(2x + -1) + 5(x + 2) = 40

Reorder the terms:
3(-1 + 2x) + 5(x + 2) = 40
(-1 * 3 + 2x * 3) + 5(x + 2) = 40
(-3 + 6x) + 5(x + 2) = 40

Reorder the terms:
-3 + 6x + 5(2 + x) = 40
-3 + 6x + (2 * 5 + x * 5) = 40
-3 + 6x + (10 + 5x) = 40

Reorder the terms:
-3 + 10 + 6x + 5x = 40

Combine like terms: -3 + 10 = 7
7 + 6x + 5x = 40

Combine like terms: 6x + 5x = 11x
7 + 11x = 40

Solving
7 + 11x = 40

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 11x = 40 + -7

Combine like terms: 7 + -7 = 0
0 + 11x = 40 + -7
11x = 40 + -7

Combine like terms: 40 + -7 = 33
11x = 33

Divide each side by '11'.
x = 3

Simplifying
x = 3

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