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3(2x-1)-2(x-3)=x-(5x-3)
We move all terms to the left:
3(2x-1)-2(x-3)-(x-(5x-3))=0
We multiply parentheses
6x-2x-(x-(5x-3))-3+6=0
We calculate terms in parentheses: -(x-(5x-3)), so:We add all the numbers together, and all the variables
x-(5x-3)
We get rid of parentheses
x-5x+3
We add all the numbers together, and all the variables
-4x+3
Back to the equation:
-(-4x+3)
4x-(-4x+3)+3=0
We get rid of parentheses
4x+4x-3+3=0
We add all the numbers together, and all the variables
8x=0
x=0/8
x=0
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