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(3*(2*x-1))/4-x+1 = x/2+1/4 // - x/2+1/4
(3*(2*x-1))/4-x-(x/2)-(1/4)+1 = 0
(3*(2*x-1))/4-x-(x/2)-1/4+1 = 0
(3*(2*x-1))/4-x-x/2-1/4+1 = 0
(2*3*(2*x-1))/(2*4)+(2*4*(-x))/(2*4)+(4*(-x))/(2*4)+(-1*2)/(2*4)+(1*2*4)/(2*4) = 0
2*3*(2*x-1)+2*4*(-x)+4*(-x)-1*2+1*2*4 = 0
4*x-4*x-6-2+8 = 0
8-6-2 = 0
8-8 = 0
0 = 0
0/(2*4) = 0
0/(2*4) = 0 // * 2*4
0 = 0
x belongs to the empty set
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