3(2x-1)/4-x+1=x/2+1/4

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Solution for 3(2x-1)/4-x+1=x/2+1/4 equation:


x in (-oo:+oo)

(3*(2*x-1))/4-x+1 = x/2+1/4 // - x/2+1/4

(3*(2*x-1))/4-x-(x/2)-(1/4)+1 = 0

(3*(2*x-1))/4-x-(x/2)-1/4+1 = 0

(3*(2*x-1))/4-x-x/2-1/4+1 = 0

(2*3*(2*x-1))/(2*4)+(2*4*(-x))/(2*4)+(4*(-x))/(2*4)+(-1*2)/(2*4)+(1*2*4)/(2*4) = 0

2*3*(2*x-1)+2*4*(-x)+4*(-x)-1*2+1*2*4 = 0

4*x-4*x-6-2+8 = 0

8-6-2 = 0

8-8 = 0

0 = 0

0/(2*4) = 0

0/(2*4) = 0 // * 2*4

0 = 0

x belongs to the empty set

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