3(2x-1)/4=4(x+2)-3/3

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Solution for 3(2x-1)/4=4(x+2)-3/3 equation: 



3(2x-1)/4=4(x+2)-3/3

We move all terms to the left:

3(2x-1)/4-(4(x+2)-3/3)=0

We calculate fractions


6x/()+(-(4(x+2)-3*4)/()=0



We calculate terms in parentheses: +(-(4(x+2)-3*4)/(), so:

-(4(x+2)-3*4)/(

We multiply all the terms by the denominator


-(4(x+2)-3*4)



We calculate terms in parentheses: -(4(x+2)-3*4), so:

4(x+2)-3*4

We add all the numbers together, and all the variables

4(x+2)-12

We multiply parentheses

4x+8-12

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

-4x+4

Back to the equation:

+(-4x+4)



We get rid of parentheses

6x/()-4x+4=0

We multiply all the terms by the denominator


6x-4x*()+4*()=0

We add all the numbers together, and all the variables

6x-4x*()=0

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