3(2x-1)=2(3x-5)+7

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Solution for 3(2x-1)=2(3x-5)+7 equation: 



3(2x-1)=2(3x-5)+7

We move all terms to the left:

3(2x-1)-(2(3x-5)+7)=0

We multiply parentheses

6x-(2(3x-5)+7)-3=0



We calculate terms in parentheses: -(2(3x-5)+7), so:

2(3x-5)+7

We multiply parentheses

6x-10+7

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We get rid of parentheses

6x-6x+3-3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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