3(2x-1)=2(x-3)=10

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Solution for 3(2x-1)=2(x-3)=10 equation: 



3(2x-1)=2(x-3)=10

We move all terms to the left:

3(2x-1)-(2(x-3))=0

We multiply parentheses

6x-(2(x-3))-3=0



We calculate terms in parentheses: -(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

6x-2x+6-3=0

We add all the numbers together, and all the variables

4x+3=0

We move all terms containing x to the left, all other terms to the right

4x=-3

x=-3/4

x=-3/4

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