3(2x-10)+4=36

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Solution for 3(2x-10)+4=36 equation: 



3(2x-10)+4=36

We move all terms to the left:

3(2x-10)+4-(36)=0

We add all the numbers together, and all the variables

3(2x-10)-32=0

We multiply parentheses

6x-30-32=0

We add all the numbers together, and all the variables

6x-62=0

We move all terms containing x to the left, all other terms to the right

6x=62

x=62/6

x=10+1/3

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