3(2x-10)=+(x-5)

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Solution for 3(2x-10)=+(x-5) equation: 



3(2x-10)=+(x-5)

We move all terms to the left:

3(2x-10)-(+(x-5))=0

We multiply parentheses

6x-(+(x-5))-30=0



We calculate terms in parentheses: -(+(x-5)), so:

+(x-5)

determiningTheFunctionDomain
(x-5)

We get rid of parentheses

x-5

Back to the equation:

-(x-5)



We get rid of parentheses

6x-x+5-30=0

We add all the numbers together, and all the variables

5x-25=0

We move all terms containing x to the left, all other terms to the right

5x=25

x=25/5

x=5

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