3(2x-10)=2(x+20)

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Solution for 3(2x-10)=2(x+20) equation: 



3(2x-10)=2(x+20)

We move all terms to the left:

3(2x-10)-(2(x+20))=0

We multiply parentheses

6x-(2(x+20))-30=0



We calculate terms in parentheses: -(2(x+20)), so:

2(x+20)

We multiply parentheses

2x+40

Back to the equation:

-(2x+40)



We get rid of parentheses

6x-2x-40-30=0

We add all the numbers together, and all the variables

4x-70=0

We move all terms containing x to the left, all other terms to the right

4x=70

x=70/4

x=17+1/2

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