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3(2x-12)=5(x+3)
We move all terms to the left:
3(2x-12)-(5(x+3))=0
We multiply parentheses
6x-(5(x+3))-36=0
We calculate terms in parentheses: -(5(x+3)), so:We get rid of parentheses
5(x+3)
We multiply parentheses
5x+15
Back to the equation:
-(5x+15)
6x-5x-15-36=0
We add all the numbers together, and all the variables
x-51=0
We move all terms containing x to the left, all other terms to the right
x=51
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