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3(2x-14)+x=15-2(5-3x)
We move all terms to the left:
3(2x-14)+x-(15-2(5-3x))=0
We add all the numbers together, and all the variables
3(2x-14)+x-(15-2(-3x+5))=0
We add all the numbers together, and all the variables
x+3(2x-14)-(15-2(-3x+5))=0
We multiply parentheses
x+6x-(15-2(-3x+5))-42=0
We calculate terms in parentheses: -(15-2(-3x+5)), so:We add all the numbers together, and all the variables
15-2(-3x+5)
determiningTheFunctionDomain -2(-3x+5)+15
We multiply parentheses
6x-10+15
We add all the numbers together, and all the variables
6x+5
Back to the equation:
-(6x+5)
7x-(6x+5)-42=0
We get rid of parentheses
7x-6x-5-42=0
We add all the numbers together, and all the variables
x-47=0
We move all terms containing x to the left, all other terms to the right
x=47
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