3(2x-2)+10=6(4x+2)+24

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Solution for 3(2x-2)+10=6(4x+2)+24 equation: 



3(2x-2)+10=6(4x+2)+24

We move all terms to the left:

3(2x-2)+10-(6(4x+2)+24)=0

We multiply parentheses

6x-(6(4x+2)+24)-6+10=0



We calculate terms in parentheses: -(6(4x+2)+24), so:

6(4x+2)+24

We multiply parentheses

24x+12+24

We add all the numbers together, and all the variables

24x+36

Back to the equation:

-(24x+36)



We add all the numbers together, and all the variables

6x-(24x+36)+4=0

We get rid of parentheses

6x-24x-36+4=0

We add all the numbers together, and all the variables

-18x-32=0

We move all terms containing x to the left, all other terms to the right

-18x=32

x=32/-18

x=-1+7/9

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