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3(2x-2)-3=x+1
We move all terms to the left:
3(2x-2)-3-(x+1)=0
We multiply parentheses
6x-(x+1)-6-3=0
We get rid of parentheses
6x-x-1-6-3=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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