3(2x-2)-5=3(x-5)+19

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Solution for 3(2x-2)-5=3(x-5)+19 equation: 



3(2x-2)-5=3(x-5)+19

We move all terms to the left:

3(2x-2)-5-(3(x-5)+19)=0

We multiply parentheses

6x-(3(x-5)+19)-6-5=0



We calculate terms in parentheses: -(3(x-5)+19), so:

3(x-5)+19

We multiply parentheses

3x-15+19

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

6x-(3x+4)-11=0

We get rid of parentheses

6x-3x-4-11=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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